Problems involving Bearings

//trigonometry lesson #8 
p.s last lesson :( 

it has honestly been such a joy to teach ya'll out there whoever you may be or where ever you may be but we really enjoy this blog post and hopefully these post definitely made a difference. thanks for the views and honestly did not expect this much!! thank you friends sooooo much!!!! xxx


here it is! the last lesson// b e a r i n g s

Examples:

this calculator is recommended for this lesson (fx82au PLUS)

problem:  A cyclist travels 10 km south, then 8 km east. Find the cyclist's bearing from her starting point to the nearest degree.

Solution:

so if we want to find θ we have to focus on △OAB, become θ  8km = opp 10km = adj
opp    (TOA)
adj 
                                                                  
tan θ = 8/10 
press into calculator shift tan (tan -1)

= 0.8

nearest degree

= *enter into calculator [bubbles]   
= 39 (degrees)         

the bearing from B to O 
= 180 (degrees) - θ 
= 180 (degrees) - 39 (degrees)
= 141 (degrees) 

therefore the cyclist bearings from B to O is 141 (degrees) from her starting point. 

judy, hannah & paul